Successive indivisible numbers allude to a grouping of at least two indivisible numbers that are close to one another with no other indivisible numbers in the middle. An indivisible number is a number that is bigger than one and that must be partitioned equitably by one and itself.

## What is consecutive prime?

A few instances of indivisible numbers are 5, 7, 11, 13, and 17. Involving these numbers in a grouping, for example, 11, 13, 17 methods would be continuous, as there are no indivisible numbers between any of these three numbers.

Then again, arrangements 7, 13, 17 wouldn’t address sequential indivisible numbers on the grounds that the indivisible number 11 can go between the 7 and the 13.

Since 2 is the main prime considerably number, It’s conceivable on the grounds that the following significant number, 4, is a composite number, similar to each and every much number after that since they are for the most part uniformly detachable by 2. As a result of all the even numbers beginning with 4 being composite, it’s difficult to have two more prime consecutive. Or then again one more method for saying it is that when you recognize an indivisible number, it’s surefire that the number promptly going before it, as well as the number succeeding it, will be composite.

**Q: Are 1, 2, and 3 the main continuous primes?**

As numerous different responses have been brought up, 1 isn’t prime and 2 and 3 are the main two continuous indivisible numbers (as any remaining even numbers are separable by 2 and subsequently not prime). In any case, I thought I’d pause for a minute to give some thinking with regards to why 1 is certifiably not an indivisible number, despite the fact that this is truly somewhat of a beside your unique inquiry.

One reason primes are so helpful/intriguing is that each and every other number can be communicated as a result of primes. For instance,

60=2^2⋅3⋅5.

Additionally, this articulation is one of a kind.